On Debian 13 (or any Linux system using GNU grep), you can use the --color option to highlight matches, but by default, it highlights all occurrences of the pattern in a line. If you want to highlight only the first occurrence of the pattern in each line, you can use a combination of grep and sed or awk.

Here’s how to do it:

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Method 1: Using grep + sed

This approach uses grep to find matching lines and sed to highlight only the first occurrence of the pattern in each line.

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grep --color=never "pattern" file.txt | sed "s/pattern/\o033[01;31m&\o033[00m/"

• --color=never: Disables grep's built-in coloring.
• sed: Replaces the first occurrence of pattern with an ANSI escape code for red color (\o033[01;31m starts red, \o033[00m resets).
• Replace "pattern" with your search term.

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Method 2: Using grep + awk

If you prefer awk, you can use it to highlight only the first occurrence:

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grep --color=never "pattern" file.txt | awk '{sub("pattern", "\033[01;31m&\033[00m"); print}'

• sub() replaces only the first occurrence of pattern with the ANSI color codes.

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Method 3: Using grep with -o and head (for single matches per line)

If you want to show only the first match per line (not the entire line), you can use:

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grep -o "pattern" file.txt | head -n 1

• -o: Outputs only the matching part.
• head -n 1: Limits to the first match.

However, this won’t show the full line context. To show the full line with only the first match highlighted, stick with Method 1 or 2.

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Permanent Solution: Alias in ~/.bashrc

To make this reusable, add an alias to your ~/.bashrc or ~/.bash_aliases:

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alias grep_first='grep --color=never "$1" | sed "s/$1/\o033[01;31m&\o033[00m/"'

Then run:

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source ~/.bashrc

Usage:

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grep_first "pattern" file.txt

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