How to avoid specifying `dialog --menu` tags *1* and *2* in the following command (not its output)?

```bash
dialog --menu 'Choose' 0 0 0 1 'Option a' 2 'Option b'
```
2/2
Jun 27, 5:13pm

To avoid specifying the tags 1 and 2 explicitly in the dialog --menu command, you can use a loop or an array to dynamically generate the menu items. This is especially useful if you have many options or want to avoid hardcoding the tags.

Here’s how you can do it in Bash:

Using an Array

You can store the options in an array and then loop through them to construct the command:

bash
#!/bin/bash

options=(
    "Option a"
    "Option b"
)

# Build the arguments for dialog
args=()
for i in "${!options[@]}"; do
    args+=("$((i+1))" "${options[i]}")
done

# Call dialog with the constructed arguments
dialog --menu 'Choose' 0 0 0 "${args[@]}"

Explanation:

  • options is an array containing the menu items.
  • The loop iterates over the indices of the array (${!options[@]}).
  • For each index i, it adds the tag ($((i+1))) and the corresponding option (${options[i]}) to the args array.
  • Finally, "${args[@]}" expands the array into the dialog command.

Result:

The command will dynamically generate the tags (1, 2, etc.) based on the array indices, so you don’t have to specify them manually.


Would you like me to adapt this for a specific use case or language?

Jun 27, 5:13pm

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