In Python how to make `matplotlib.pyplot.show` also run `matplotlib.pyplot.figure`?
Feb 22, 5:14pm
In Python, when you use matplotlib.pyplot.show(), it displays all the figures you've created but does not automatically create a new figure for you. If you want to ensure that a new figure is created every time you call plt.show(), you need to explicitly call plt.figure() before plotting.
How to Combine plt.figure() and plt.show()
If you want to create a new figure and then display it, you can do:
python
import matplotlib.pyplot as plt
# Create a new figure
plt.figure()
# Plot something (optional)
plt.plot([1, 2, 3], [4, 5, 6])
# Show the figure
plt.show()
Automating the Process
If you want to ensure that a new figure is created every time you call plt.show(), you can create a custom function:
python
import matplotlib.pyplot as plt
def show_with_new_figure():
plt.figure() # Create a new figure
plt.show() # Show the figure
# Usage
show_with_new_figure()
Why This Works
plt.figure() creates a new figure window.
plt.show() displays the current figure(s).
Note
If you call plt.show() multiple times in a script, it will block execution until all figure windows are closed. To avoid this, use plt.ion() for interactive mode or close figures manually with plt.close().
Would you like help with a specific use case or more advanced customization?
Feb 22, 5:14pm
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