In Python how to make `matplotlib.pyplot.show` also run `matplotlib.pyplot.figure`?
Feb 22, 5:14pm

In Python, when you use matplotlib.pyplot.show(), it displays all the figures you've created but does not automatically create a new figure for you. If you want to ensure that a new figure is created every time you call plt.show(), you need to explicitly call plt.figure() before plotting.

How to Combine plt.figure() and plt.show()

If you want to create a new figure and then display it, you can do:

python
import matplotlib.pyplot as plt

# Create a new figure
plt.figure()

# Plot something (optional)
plt.plot([1, 2, 3], [4, 5, 6])

# Show the figure
plt.show()

Automating the Process

If you want to ensure that a new figure is created every time you call plt.show(), you can create a custom function:

python
import matplotlib.pyplot as plt

def show_with_new_figure():
    plt.figure()  # Create a new figure
    plt.show()     # Show the figure

# Usage
show_with_new_figure()

Why This Works

  • plt.figure() creates a new figure window.
  • plt.show() displays the current figure(s).

Note

  • If you call plt.show() multiple times in a script, it will block execution until all figure windows are closed. To avoid this, use plt.ion() for interactive mode or close figures manually with plt.close().

Would you like help with a specific use case or more advanced customization?

Feb 22, 5:14pm

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