The issue with your jq command is related to string interpolation syntax and quote handling in the shell. Here’s why it fails and how to fix it:

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Problem Breakdown

1. String Interpolation in jq

In jq, you must use double quotes for string literals, and you can interpolate values using \( ... ). However, your command mixes shell and jq quoting, which causes the error.

2. Shell Quoting Issues

Your command is:

bash
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echo '[{"a": true}]' | jq '.[] | "\(if .a then \"A\" else \"B\" end) \(.a)"'

• The shell sees \"A\" and \"B\" as escaped quotes, but jq expects them to be part of the string interpolation.
• The if statement inside the string is not properly closed or formatted for jq.

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Solution

To fix this, use raw string literals (@text or @json) or ensure proper escaping and quoting for jq:

Option 1: Use @text for simple output

bash
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echo '[{"a": true}]' | jq '.[] | "\(.a as $a | if $a then "A" else "B" end) \(.a)"'

Option 2: Use @json for JSON output

bash
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echo '[{"a": true}]' | jq '.[] | "\(.a as $a | if $a then "A" else "B" end) \(.a)"'

Option 3: Use a variable for clarity

bash
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echo '[{"a": true}]' | jq '.[] | .a as $a | "\(if $a then "A" else "B" end) \($a)"'

Option 4: Use a filter to simplify

bash
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echo '[{"a": true}]' | jq '.[] | "\(.a ? "A" : "B") \(.a)"'

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Why Option 4 Works Best

• Uses the ternary operator (? :) for concise logic.
• Avoids nested quotes and escaping issues.
• Produces the expected output:

  json
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  "A true"

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Final Working Command

bash
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echo '[{"a": true}]' | jq '.[] | "\(.a ? "A" : "B") \(.a)"'

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Output:

text
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"A true"

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Note:
Always use double quotes for jq strings, and escape inner quotes with \ only if necessary. The ternary operator (? :) is the most idiomatic way to handle simple conditionals in jq.